Question

Find the value of (2401)^0.16 × (49)^0.18

1. 6
2. 11
3. 9
4. 14
5. 7

Answer 1

Correct Answer - Option 5 : 7

Given:

(2401)0.16 × (49)0.18

Concept used:

(aⁿ)^m = a^nm

aⁿ × a^m = a^{n + m}

Calculation: 

(2401)0.16 × (49)0.18

⇒ (7⁴)0.16 × (7²)0.18

⇒ 7^0.64 × 7^0.36

⇒ 7^{0.64 + 0.36}

⇒ 7^1.00

⇒ 7

∴ The required value is 7.