Question

During an epidemic, Chaman Lal a greedy shopkeeper promises to sell his goods at 44% loss but he uses 910 gm weight instead of 1 kg. Find his actual loss% (approx.)
1. 64.83%
2. 46.38%
3. 38.46%
4. 28.64%

Answer 1

Correct Answer - Option 3 : 38.46%

Given∶

Loss = 44%

Original weight = 1 kg = 1000 gm

Altered weight = 910 gm

Formula Used∶

Gain% or Loss% = [(100 – Loss%) × (Original weight/Altered weight)] – 100

Calculation∶

Loss = 44%

Original weight = 1 kg = 1000 gm

Altered weight = 910 gm

Gain% or Loss% = [(100 – 44) × (1000/910)] – 100 = [56 × 1000/910] – 100 = [5600/91] – 100 = 61.54 – 100 = - 38.46%

Here, the negative sign shows Loss.

∴ His actual Loss% is of 38.46%.