Correct Answer - Option 4 : 9230 ml
Given:
Sulfuric acid with 90% concentration = 1.5 litres
First class = 20 students
One student = 10 ml of sulfuric acid mixture
Second class onwards = 10 students
Formula used:
Arithmetic progression: Tn = a + (n – 1) d
Sn = (a + L) × (n/ 2)
Calculation:
Class of 12 hence, amount of mixture replaced = 20 × 10
⇒ In first class amount of mixture replaced with water = 200 ml
Second class onwards only 10 students
⇒ from second class amount of mixture replaced = 100 ml
Arithmetic progression looks like:-
⇒ 200 + 300 + 400 + 500 + 600 + … + 1400 + 1500
⇒ Here, a = 200, d = 100, n = 13 (∵ the last 1500 ml would be pure water and hence it doesn’t need replacement)
⇒ 1400 = 200 + ((n – 1) × 100)
⇒ 1200 = (n – 1) × 100
⇒ n = 13
Total sum of replaced water,
⇒ S = (200 + 1400) × (13/ 2)
⇒ S = 9230 ml
∴ required total quantity of water for replacing mixture till carton is empty is 9230 ml