Correct Answer - Option 3 : 21
Let the number of males be M and the number of females be F.
Each male or each female will shake hands with each of the member of the opposite sex.
The total number of handshakes = M x F = 24
Possibilities for the number of males and females in the society (not necessarily in the same order) = (2, 12), (3, 8), (4, 6), (1, 24)
In case of (2, 12), the number of hugs would be = 2C2 + 12C2 = \( 2!/(2! х 1) + 12!/(2! х 10!)\) = 1 + 66 = 67
Clearly, it is not in the option.
In case of (3, 8), the number of hugs would be = 3C2 + 8C2 = \( 3!/(2! х 1) + 8!/(2! х 6!)\) = 3 + 28 = 31
Clearly, it is not in the option either.
In case of (4, 6), the number of hugs would be = 4C2 + 6C2 = \( 4!/(2! х 2!) + 6!/(2! х 4!)\) = 6 + 15 = 21
Clearly, it is one of the options.
Hence, 21 possible hugs are there according to the given data.