Correct Answer - Option 2 : [-2, 0]
Concept:
Domin of sin-1 x is [-1, 1]
Adding or subtracting the same quantity from both sides of an inequality leaves the inequality symbol unchanged.
Calculation:
Given: f(x) = sin-1 (x + 1)
As we know, domin of sin1 x is [-1, 1]
Therefore, -1 ≤ (x + 1) ≤ 1
subtracting 1 in above inequality,
⇒ -1 - 1 ≤ x + 1 - 1 ≤ 1 - 1
⇒ -2 ≤ x ≤ 0
∴ Domin of sin-1 (x + 1) is [-2, 0]
