Correct Answer - Option 1 :
\(\rm \frac{3a}{2c^2}\log\left|{b^2+c^2x^2}\right|+C\)
Concept:
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Integration by substitution: If we substitute x = f(t), then dx = f'(t) dt and ∫ f(x) dx = ∫ f[f(t)] f'(t) dt.
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\(\rm \int\frac{dx}{x}=\log x+C\).
Calculation:
Let I = \(\rm \int\frac{3ax}{b^2+c^2x^2}\ dx\).
Substituting b2 + c2x2 = t
⇒ (2c2x)dx = dt
⇒ xdx = \(\rm \frac{dt}{2c^2}\)
⇒ I = \(\rm \frac{3a}{2c^2}\int \frac1t\ dt\)
⇒ I = \(\rm \frac{3a}{2c^2}\log |t| + C\)
⇒ I = \(\rm \frac{3a}{2c^2}\log\left|{b^2+c^2x^2}\right|+C\).