Question

Find the smallest three digit number which is divisible by 2, 3 and 5 gives same remainder 1
1. 121
2. 152
3. 992
4. 112

Answer 1

Correct Answer - Option 1 : 121

Given

Smallest 3 digit number which was divisible by 2, 3 and 5 and gives same remainder of 1

Calculation

The smallest 3 digit number is 100

⇒ LCM of 2, 3 and 5 is 30

⇒ (100)/30 gives remainder 10

⇒ Smallest 3 digit number divisible by 30 is (30 - 10 + 100) = 120

∴  So smallest 3 digit number divisible by 2, 3 and 5 and gives remainder of 1 is 120 + 1 = 121