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A man travels on his bicycle at a speed of 5 m/sec. A train coming from behind with a speed of 50 m/sec crosses him in 10 seconds in the same direction. Find the time taken by the train in seconds to cross a platform of 550 m?

1. 19 
2. 21
3. 20
4. 15

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Correct Answer - Option 3 : 20


The speed of a man traveling on a bicycle is 5 m/sec.

The speed of the train coming from behind is 50 m/sec which crosses him in 10 seconds.

The length of the platform is 550 m.

Formula Used:

Relative Speed = Distance/Time


Let the length of the train be L.

⇒ L = (50 – 5) × 10

⇒ L = 450 m

As speed of the train is 50 m/sec, then the time(T) taken by the train to cross the platform of length 550 m will be

⇒ (450 + 550) = (50) × T

⇒ T = 1000/50 = 20 sec

∴ The time taken by the train to cross the platform is 20 seconds.

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