Correct Answer - Option 2 : B = 3A
Given:
A = 382 - 326 - 5 × (1/3) of 60 + {32 × (20 - 15)}
B = 6 ÷ 18 × 75 - {(2/3) of 90 - 114 ÷ 3}
Concept:
BODMAS Principle:
Solve for:
1) Expressions in the bracket first. Apply BODMAS rule inside the bracket also.
2) Operations 'of' (Multiplication) and 'order' (exponent)
3) Division
4) Multiplication
5) Addition and Subtraction
Calculation:
A = 382 - 326 - 5 × (1/3) of 60 + {32 × (20 - 15)}
⇒ 56 - (5 × 20) + (9 × 5)
⇒ 56 - 100 + 45 = 1
∴ A = 1
Now,
B = 6 ÷ 18 × 75 - {(2/3) of 90 - 114 ÷ 3}
⇒ (1/3) × 75 - (60 - 38)
⇒ 25 - 22 = 3
∴ B = 3
Now we have A = 1 and B = 3
∴ B = 3A