# Solve for A and B and choose the correct relation between A and B if: A = 382 - 326 - 5 × (1/3) of 60 + {32 × (20 - 15)} and B = 6 ÷ 18 × 75 - {(2/3

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Solve for A and B and choose the correct relation between A and B if:

A = 382 - 326 - 5 × (1/3) of 60 + {32  × (20 - 15)} and

B = 6 ÷ 18 × 75 - {(2/3) of 90 - 114 ÷ 3}

1. A = 3B
2. B = 3A
3. A = 2B
4. B = 2A

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Correct Answer - Option 2 : B = 3A

Given:

A = 382 - 326 - 5 × (1/3) of 60 + {3 × (20 - 15)}

B = 6 ÷ 18 × 75 - {(2/3) of 90 - 114 ÷ 3}

Concept:

BODMAS Principle:

Solve for:

1) Expressions in the bracket first. Apply BODMAS rule inside the bracket also.

2) Operations 'of' (Multiplication) and 'order' (exponent)

3) Division

4) Multiplication

Calculation:

A = 382 - 326 - 5 × (1/3) of 60 + {3 ×  (20 - 15)}

⇒ 56 - (5 × 20) + (9 × 5)

⇒ 56 - 100 + 45 = 1

∴ A = 1

Now,

B = 6 ÷ 18 × 75 - {(2/3) of 90 - 114 ÷ 3}

⇒ (1/3) × 75 - (60 - 38)

⇒ 25 - 22 = 3

∴ B = 3

Now we have A = 1 and B = 3

∴ B = 3A