Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
67 views
in Aptitude by (115k points)
closed by

Solve for A and B and choose the correct relation between A and B if:

A = 382 - 326 - 5 × (1/3) of 60 + {32  × (20 - 15)} and 

B = 6 ÷ 18 × 75 - {(2/3) of 90 - 114 ÷ 3}


1. A = 3B
2. B = 3A
3. A = 2B
4. B = 2A

1 Answer

0 votes
by (114k points)
selected by
 
Best answer
Correct Answer - Option 2 : B = 3A

Given:

A = 382 - 326 - 5 × (1/3) of 60 + {3 × (20 - 15)}

B = 6 ÷ 18 × 75 - {(2/3) of 90 - 114 ÷ 3}

Concept:

BODMAS Principle:

Solve for:

1) Expressions in the bracket first. Apply BODMAS rule inside the bracket also.

2) Operations 'of' (Multiplication) and 'order' (exponent)

3) Division

4) Multiplication

5) Addition and Subtraction

Calculation: 

A = 382 - 326 - 5 × (1/3) of 60 + {3 ×  (20 - 15)}

⇒ 56 - (5 × 20) + (9 × 5)

⇒ 56 - 100 + 45 = 1

∴ A = 1

Now, 

B = 6 ÷ 18 × 75 - {(2/3) of 90 - 114 ÷ 3}

⇒ (1/3) × 75 - (60 - 38)

⇒ 25 - 22 = 3

∴ B = 3

Now we have A = 1 and B = 3

∴ B = 3A

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...