Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
3.4k views
in Co-ordinate geometry by (30 points)
recategorized by

The two circles x2 + y2 − 2 x + 6 y + 6 = 0 and x2 + y2 − 5 x + 6 y + 15 = 0 touch each other. The equation of their common tangent is :

Please log in or register to answer this question.

1 Answer

0 votes
by (41.1k points)

Common tangent (x2 + y2 - 2x + 6y +6) - (x2 + y2 - 5x + 6y + 15) = 0

= - 2x + 5x + 6y - 6y + 6 - 15 = 0

= 3x - 9 = 0

= x = \(\cfrac93\) = 3

= x = 3

Hence, x = 3 is common tangent

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...