Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
235 views
in Algebra by (239k points)
closed by

If x + y + z = 20 and x2 + y2 + z2 = 40 so, find the value of x3 + y3 + z3 – 3xyz.


1. –2400
2. –2800
3. –2700
4. –2600

1 Answer

0 votes
by (237k points)
selected by
 
Best answer
Correct Answer - Option 2 : –2800

Given:

x + y + z = 20 and x2 + y2 + z2 = 40

Formula used:

(x + y + z)2 = x2 + y2 + z2 + 2(xy + yz + zx)

x3 + y3 + z3 – 3xyz = (x + y + z){x2 + y2 + z2 – (xy + yz + zx)}

Calculation:

(x + y + z)2 = x2 + y2 + z2 + 2(xy + yz + zx)

⇒ (20)2 = 40 + 2(xy + yz + zx)

⇒ 400 = 40 + 2(xy + yz + zx)

⇒ 2(xy + yz + zx) = 360

⇒ (xy + yz + zx) = 180

Then, x3 + y3 + z3 – 3xyz = (x + y + z){x2 + y2 + z2 – (xy + yz + zx)}

⇒ 20 × (40 – 180)

⇒ 20 × (– 140)

⇒ –2800

∴ The value of x3 + y3 + z3 – 3xyz is –2800.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...