Correct Answer - Option 3 : 1/12
Given:
Two dice are thrown simultaneously
Formula Used:
P(E) = n(E)/n(S)
Where,
n(E) = Number of favourable events
n(S) = Number of possible outcomes
Calculation:
When two dice throw simultaneously, then total possible outcomes
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2),..............................., (2, 6)
............................................................
............................................................
(6, 1), (6, 2), ................................(6, 6)
Number of possible outcomes n(S) = 6 × 6
⇒ 36
Number of favourable events n(E) = {(4,6), (6,4), (5,5)} = 3
⇒ n(E) = 3
Required probability of getting a total of 10
P(E) = 3/36
⇒ 1/12
∴ The probability of getting a total of 10 is 1/12.
