Question

The sleeper density of a broad gauge track is (M + 7) in metric units, where M is length of rail in metres. The number of sleepers for 1.024 km length of track is:
1. 1700
2. 1500
3. 1600
4. 1900

Answer 1

Correct Answer - Option 3 : 1600

On Indian railways standard length of BG rail = 13 m 

So, total no. of rail required in 1.024 km or 1024 m

= 1024/13 = 78.78 = 80 (in round figure)

Sleeper density = M + 7

M = length of rail

So, sleeper density = 13 + 7 = 20

No. of sleepers = 20 × 80 = 1600