Electrolysis of molten PbBr2 takes place as follows:
PbBr2 ⇋ Pb2+ + 2Br-
Pb2+ + 2e → Pb(at cathode)
2Br- - 2e- (Reduction) → 2[Br](at anode)
2 [Br] → Br2 ↑
Thus reduction takes place at cathode while oxidation takes place at anode. Therefore, electrolysis of molten PbBr2 is a redox reaction.