Correct Answer - Option 2 : 1/6
Given
Two sides are thrown
Concept
Multiplication theorem on probability
If A and B are two events associated with a random experiment, then
P(A. B) = P(A) .P(B/A)
Calculation
Let A is the event of occurrence of 4 on first dice
⇒ n(A) = 6 i.e[(4,1), (4,2), (4,3), (4,4); (4,6) and (4,5)]
and B is the event of occurrence of such numbers on both dice whose sum is 5 = [(4,1); (3,2); (2,3) and (1,4)]
Thus, A. B = (4,1)
⇒ n(A B) = 1
P(B/A) = 1/6