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A urn contains 7 blue pens & 6 red pens . 3 pens are drawn at random & then find the probability that 2 pens are blue & 1 pen is red.
1. 63/143 
2. 7/143 
3. 6/143
4. 7/189
5. 71/143

1 Answer

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Best answer
Correct Answer - Option 1 : 63/143 

Given

Number of blue pens = 7

Number of red pens = 6

Formula used

P(E) = Number of favourable outcomes/Total number of outcomes

Calculation

Let E is an event of drawing 2 blue pens and 1 red pens

P(E) = (7 C 2 × 6 C 1 )/ 13 C 3

⇒ (21 × 6)/(13 × 22)

⇒ 63/143

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