Correct Answer - Option 1 : 288
Concept used:
Number of all the permutations of n things = n!
Calculation:
The given word is ANUBHAW in this word we take all consonants as one letter
AUANBHW in this word NBHW treat as one letter
This arrangement has 4 letters of which A appears two times
⇒ Number of ways = 4!/2!
⇒ (4 × 3 × 2!)/2!
⇒ 12
Now, four consonants can be arranged among them as 4! = 4 × 3 × 2× 1
⇒ 24 ways
Required number of ways = 12 × 24
⇒ 288
∴ The required number of ways is 288
