# The resolution of 4 Bit counting ADC is 05 V For an analog input 5.8 volt the output of ADC will be_____

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1. 1100
2. 1111
3. 1010
4. 1011

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Correct Answer - Option 1 : 1100

Concept:

• Analog-to-Digital Converters (ADCs) transform an analog voltage to a binary number (a series of 1’s and 0’s).
• Then eventually to a digital number (base 10) for reading on a meter, monitor, or chart.
• The ADC resolution depends upon the number of bits used to represent the digit number.
• As the number of bits increases the resolution of an Analog to Digital Converter improves and the quantization error decreases.

Resolution for n – bit A/D converter  will be:

$R= \frac{V_{FS} \ \times \ (2^ib^i)}{{{2^n} - 1}}$

Where

R = Resolution

VFS is reference voltage 'or' Full-scale voltage

n = number of bits

2ibi gives output voltage value.

Calculation:

Given:

VFS = 5.8 V

n = 4

R = 05 V

$5= \frac{5.8 \ \times \ 2^ib^i}{{{2^{4}} - 1}}$

$2^ib^i= \frac{5 \ \times \ 15}{{5.8}}$

2ibi = 12.93 V ≈ 12 V

In bits, the output voltage will be 1100

Hence option (1) is the correct answer.

The resolution of DAC is a change in analog voltage corresponding to the LSB bit increment at the input.

The resolution (R) is calculated as:

$R= \frac{{{V_{FS}}}}{{{2^N} - 1}}$

No. of levels = 2N – 1

Vr is reference voltage 'or' Full-scale voltage