Correct Answer - Option 1 :
\(\frac{{{Z^2}}}{{(Z + 1)(Z - 1)}}\)
y(n) + y(n – 1) = x(n)
Taking Z transform we get
Y(Z) + Z-1 Y(Z) = X(Z)
\(\frac{{Y\left( Z \right)}}{{X\left( Z \right)}} = \frac{1}{{1 + {Z^{ - 1}}}}\)
Now,
x(n) = u(n)
\(Y\left( Z \right) = \frac{1}{{\left( {1 + {Z^{ - 1}}} \right)}} \times \left( Z \right)\)
\(= \frac{1}{{\left( {1 + {Z^{ - 1}}} \right)}} \times \frac{1}{{\left( {1 - {Z^{ - 1}}} \right)}}\)
\(= \left( {\frac{Z}{{Z + 1}}} \right)\left( {\frac{Z}{{Z - 1}}} \right)\)
\(= \frac{{{Z^2}}}{{\left( {Z + 1} \right)\left( {Z - 1} \right)}}\)