Correct Answer - Option 4 : 75 r.p.m
Concept:
In a 3-phase induction motor, the synchronous speed & slip can be calculated as
\({N_s} = \;\frac{{120f}}{P}\)
\(s = \;\frac{{{N_s} - {N_r}}}{{{N_s}}}\)
Nr = Ns (1 – s)
Where, Ns = Synchronous speed in rpm,
Nr = Rotor speed in rpm,
s = Slip of the machine,
f = Supply frequency in Hz,
P = Number of poles,
The speed of the rotor m.m.f. relative to the rotor, structure = Ns - Nr
Calculation:
Given
f = 50 Hz
P = 4
s = 0.05
\({N_s} = \;\frac{{120f}}{P}\)
\({N_s} = \;\frac{{120\times50}}{4}=1500\) rpm
Nr = Ns (1 – s)
Nr = 1500 (1 – 0.05)
Nr = 1425 rpm
The speed of the rotor m.m.f. relative to the rotor, structure = 1500 - 1425
= 75 rpm