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if  nPr = 720 and nCr = 6, then find value of r! ?
1. 5!
2. 4!
3. 3!
4. 2!

1 Answer

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Correct Answer - Option 1 : 5!

Formula Used:

nPr =n!/(n-r)!

nCr = n!/[(n-r)! r! ]

nPr/nCr = r!

Calculation:

Given:

nPr = 720

nCr = 6

nPr/nCr = r!

r! = 720/6

r! = 120

r! = 5 × 4 × 3 × 2 × 1

r = 5 

∴ The value of r! = 5! 

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