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A real image of height twice that of the object was formed at a distance of 20 cm from the pole of a concave mirror. what is the focal length of the mirror ?
1. 5.56 cm
2. 6.67 cm
3. 7.78 cm
4. 8.89 cm

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Correct Answer - Option 2 : 6.67 cm

Concept:

Mirror

  • A mirror is a polished surface that reflects the light incident on it.
  • Types of the mirror:
    1. Plane mirror
    2. Spherical mirror
    • ​Spherical Mirror includes a concave mirror and convex Mirror

​Concave and Convex Mirror

  • Concave mirrors have reflecting surface inward and the convex mirror has reflecting surface outward. 
  • The concave mirror has a focus toward which it converges reflecting rays falling on it parallel to principal axis. 
  • Convex mirror diverges ray of light falling on it such that it appears to be coming from an imaginary point beyond it known as focus.
  • The distance between the mirror and its focus is called the focal length.

​​Mirror formula:

  • The expression which shows the relation between object distance (u)image distance (v), and focal length (f) is called the mirror formula.

\(⇒\frac{1}{v} + \frac{1}{u} = \frac{1}{f}\)

Linear magnification (m):

  • It is defined as the ratio of the height of the image (hi) to the height of the object (ho).

\(⇒ m=\frac{h_{I}}{h_{O}}=-\frac{v}{u}\)

Sign Convention for mirror

  • The left side of the mirror, where the object is placed is considered as positive and behind the mirror negative.
  • Erect objects are considered positive and inverted as negative.
  • The focal length for the concave mirror is negative and the convex mirror is positive. 

Calculation:

Given, the image distance v = - 20 cm (in front of mirror is negative distance)

focal length f = ?

Magnification m = - 2 (real image so inverted, so magnification will be with minus sign)

\(⇒ - 2 = -\frac{v}{u}\)

⇒ v = 2u 

v = - 20cm, So u = - 10 cm

So, object is kept 10 cm infornt of mirror

Now, applying mirror formula

\(⇒\frac{1}{v} + \frac{1}{u} = \frac{1}{f}\)

\(⇒\frac{1}{-20} + \frac{1}{-10} = \frac{1}{f}\)

\(⇒ f = \frac{1+2}{-20} = -\frac{20}{3}\)

⇒ f = - 6.67 cm

The minus sign indicates it is in front of the mirror.

So, the focal length is 6.67 cm.

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