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A time study of a machine operation recorded a cycle time of 7, 6, 7, 8 minute. The analyst rated the observed worker 80%. The allowance fraction is 0.1. The standard time is
1. 5.22 minutes
2. 6.22 minutes
3. 7.22 minutes
4. 7.0 minutes

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Correct Answer - Option 2 : 6.22 minutes

Concept:

When time study is performed then

Observed Time (OT): It is the time observed by an observer

Normal Time (NT): It is the time required to complete a job by a normal average worker under normal working condition.

NT = OT × Rating Factor

Standard Time: It is the required to complete a job by taking all the uncertainty related to the production system into account

Allowances: It is the extra time provided to the worker above the NT to work continuously for long duration.

ST = NT + Allowances

Allowance are always given with respect to normal time.

Allowance = % of Normal Time

Calculation:

Given:

Given that cycle time 7.0, 6.0, 7.0, 8.0 minutes

\(Average\;OT = \frac{{7\; + \;6\; + \;7\; + \;8}}{4} = 7\;minutes\)

Rating Factor = 0.8

NT = OT × RF = 7 × 0.8 = 5.6 minutes

Allowance Fraction = 0.1

Allowance = 5.6 × 0.1 = 0.56 minutes

ST = NT + Allowance = 5.6 + 0.56 = 6.16 minutes ≃ 6.22 minutes

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