Correct Answer - Option 4 : 400 cm
Concept:
For venturimeter,
\({\rm{Pressure\;head\;difference\;}}\left( h \right) = x \times \left( {\frac{{{S_m}}}{{{S_0}}} - 1} \right)\)
Where x = reading, Sm = liquid with higher specific gravity, So = liquid with lower specific gravity.
Calculation:
Given:
So = 0.8, x = 0.25 m = 0.2 m, D1 = 0.2 m, D2 = 0.1 m, Sm = 13.6
Now,
\({\rm{Pressure\;head\;difference\;}}\left( h \right) = x \times \left( {\frac{{{S_m}}}{{{S_0}}} - 1} \right)\)
\(h = 0.25\left( {\frac{{13.6}}{{0.8}} - 1} \right)\)
∴ h = 4 m = 400 cm
The rate of flow through the Venturimeter is given as:
\({\rm{Rate\;of\;flow\;}}\left( Q \right) = \frac{{{C_d} \cdot {A_1}{A_2}\sqrt {2gh} }}{{\sqrt {A_1^2 - A_2^2} }}\)
Where a0 = area at the throat. a1 = area at the inlet, and h = difference in head.