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3 married couples have bought 6 seats in the same row for a talent show. How many different ways can they be seated with no restrictions?


1. 840
2. 760
3. 740
4. 720

1 Answer

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Best answer
Correct Answer - Option 4 : 720

Given:                             

3 married couples have bought 6 seats in the same row for a talent show.

Formula used:

n! = n × (n – 1) × (n – 2) ……………………….3 × 2 × 1

Calculation:

I like to think of this as a queue, choosing places to sit.

The first person has 6 places they could sit, the second has 5, third has 4 and so on. Multiply them together

⇒ 6! = 6 x 5 x 4 x 3 x 2 x 1

⇒ 720

∴ Different ways can they be seated with no restrictions is 720.

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