Correct Answer - Option 4 : 720
Given:
3 married couples have bought 6 seats in the same row for a talent show.
Formula used:
n! = n × (n – 1) × (n – 2) ……………………….3 × 2 × 1
Calculation:
I like to think of this as a queue, choosing places to sit.
The first person has 6 places they could sit, the second has 5, third has 4 and so on. Multiply them together
⇒ 6! = 6 x 5 x 4 x 3 x 2 x 1
⇒ 720
∴ Different ways can they be seated with no restrictions is 720.