Correct Answer - Option 3 : 19 liter
Given:
100 liter of pure milk.
10 liter of milk is replaced with water two times.
Formula Used:
Final quantity = Initial quantity (1 - X/C)n,
C = capacity of a vessel
x = quantity taken out at a time
n = number of process
Calculation:
Final quantity = Initial quantity (1 - X/C)n
⇒ Final quantity = 100(1 – 10/100)2
⇒ Final quantity = 100(1 – 1/10)2
⇒ Final quantity = 100(9/10)2
⇒ Final quantity = 100 × 9/10 × 9/10
⇒ Final quantity = 81
81 liter of milk will be remaining.
Now the amount of water,
⇒ 100 – 81
⇒ 19
∴ The amount of water in the mixture is 19 liter.