Correct Answer - Option 3 : 4
Given:
Acid and Water in ratio = 6 : 1
Water added to the mixture = 12 litres
The Final ratio of acid to water = 3 : 2
Calculation:
Let the amount of acid and water initially be 6x and x
The initial ratio of acid to water = 6x : x
Adding water to mixture litres = x + 12
According to question,
[6x/(x + 12)] = 3/2
⇒ 12x = 3x + 36
⇒ 9x = 36
⇒ x = 36/9 = 4
∴ The quantity of water in the original mixture is 4 litres