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The maximum demand on a power station is 200 kW. If the annual load factor is 50%, find the total energy generated in a year.
1. 576 MWh
2. 87.6 MWh
3. 876 MWh
4. 57.6 MWh

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Correct Answer - Option 3 : 876 MWh

Concept:

Load factor: The ratio of average load to the maximum demand during a given period is known as the load factor.

Load factor = average load/maximum demand

If the plant is in operation of T hours

\(Load\;factor = \frac{{Avearge\;load \times T}}{{Maximum\;demand \times T}}\)

\(= \frac{{Units\;generated\;in\;T\;hours}}{{Maximum\;demand \times T}}\)

  • The load factor may be daily load factor, monthly or annually if the period considered is a day or month or year
  • Load factor is always less than 1 because the average load is smaller than the maximum demand
  • It plays a key role in determining the overall cost per unit generated
  • Higher the load factor of the power station, lesser will be the cost per unit generated, it is because higher load factor means lesser maximum demand
  • The station capacity is so selected that it must meet the maximum demand
  • Now, lower maximum demand means a lower capacity of the plant which reduces the cost of the plant

 

Calculation:

Given that, maximum demand = 200 kW

Annual load factor = 50% = 0.5

\(\Rightarrow 0.5 = \frac{E}{{200 \times 365 \times 24}}\)

⇒ E = 876 MWh

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