Correct Answer - Option 2 : 16.7%
Concept:
Plant use factor: It is the ratio of kWh generated to the product of plant capacity and the number of hours for which the plant was in operation.
\(Plant\;use\;factor = \frac{{Station\;output\;in\;kWh}}{{Plant\;capacity \times hours\;of\;use}}\)
Calculation:
Given that, station output = 7.35 × 106 kWh = 7.35 × 103 MWh
Plant capacity = 20 MW
Hours of use = 2190
Plant use factor \( = \frac{{7.35 \times {{10}^3}}}{{20 \times 2190}} \times 100 = 16.78\% \)