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A wire of length 50 cm moves at right angles to its length at 50 m/s in a uniform magnetic field of density 1T. Find the EMF induced in the conductor when the direction of motion is inclined at 30° to the direction of the field.
1. 25 V
2. 6.75 V
3. 12.5 V
4. 50 V

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Correct Answer - Option 3 : 12.5 V

Concept:

The emf induced when the conductor moves at an angle θ to the direction of a uniform magnetic field is given by:

EMF = BLv sin θ

B = Magnetic field in Tesla

L = Length of the conductor

v = velocity of the conductor

Calculation:

Given L = 50 cm = 0.5 m, B = 1 T, v = 50 m/s, and θ = 30°

The emf induced when the conductor moves at an angle of 30° to the direction of the field will be:

EMF = (1) (0.5) (50) sin 30°

\(EMF=100\times \frac{1}{2}\)

EMF = 12.5 V

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