Correct Answer - Option 4 : 750 rpm
Concept:
In a three-phase induction motor, synchronous speed is
\({N_s} = \frac{{120f}}{P}\)
Where Ns = Synchronous Speed in rpm
f = supply frequency in Hz
P = number of poles
Rotor speed, Nr = Ns (1 – s)
Calculation:
Given that,
P = 8, f = 50 Hz
The synchronous speed of the induction motor is,
\({N_s} = \frac{{120 \times 50}}{8} = 750\;rpm\)