Correct Answer - Option 2 : (-at², 2at)
Calculations:
Consider the parabola y2 = -4axy2=4ax.y2=4ax.
We want to replace the variables x and y by the parameter t.
We see that the LHS is a square.
⇒ When x is parameterised, the RHS should become a perfect square.
⇒ The parameterised form of x should be -at2
y2 = - 4ax
⇒y2 = - 4a (- at2)
⇒y2 = 4a2t2
⇒y = 2at.
⇒ The parameterised form of y should be 2at.
Hence, the parametric coordinate of any point of the parabola y2 = -4ax is (-at², 2at).