Correct Answer - Option 3 : 10.95 A
Concept:
1 HP = 746 Watt.
Efficiency is the ratio of output power to the motor to input power to the motor.
Electrical input power P = V × I × cos ϕ
Where, P = Power
V = Supply Voltage
I = Input Current
cos ϕ = Power Factor (ϕ = angle between supply voltage and input current)
Note:- If rating of any machine is given that means that is its output power rating.
Calculation:
Given: Output power rating of single phase Induction motor = 2 HP = 2 × 746 W = 1492 W.
Supply voltage (V) = 240 V
Efficiency (η) = 70 % = 0.7
Power factor (cos ϕ) = 0.8
\(\eta = \frac{{Output\;power}}{{Input\;power}}\)
\(Input\;Power\;\left( P \right) = \;\frac{{Output\;power}}{\eta } = \;\frac{{1492}}{{0.7}} = 2131.43\;W\)
Now P = V × I × cos ϕ
2131.43 = 240 × I × 0.8
I = 11.1 A
So our closest possible answer is 10.95 A.