Correct Answer - Option 2 : E/2
Concept:
If the energy of signal x(t) is E then
The energy of signal Ax(Bt + c) is \(\frac{{{A}^{2}}E}{\left| B \right|}\)
Calculation:
Comparing with the standard equation
A = 1
B = 2
C = 0
Energy of y(t) \(=\frac{{{A}^{2}}E}{\left| B \right|}\)
\(=\frac{E}{2}\)
Hence, option 2 is correct.