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Given that \((1^2 + 2^2 + 3^2 + ...+10^2)=385\), the value of \((2^2 +4^2 +6^2 + ...+ 20^2)\) is equal to

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Given that \((1^2 + 2^2 + 3^2 + ...+10^2)=385\), the value of \((2^2 +4^2 +6^2 + ...+ 20^2)\) is equal to
1. 770
2. 1155
3. 1540
4. (385)2
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Correct Answer - Option 3 : 1540

Given:

 \((1^2 + 2^2 + 3^2 + ...+10^2)=385\)

Calculation:

\(2^2(1^2 +2^2 +3^2 + ...+ 10^2)\)

⇒ 4 × 385 = 1540

∴ The value of \((2^2 +4^2 +6^2 + ...+ 20^2)\) is equal to 1540.

 

 

 

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