Correct Answer - Option 2 : 90
Answer: 2
Given :
Two trains of length 180 m and 270 m
And crosses each other in 10.8 sec
Concept :
1m/s = 5/18 kmph
Relative speed when the train in opposite direction = (S1 + S2)
Where S is the speed.
Speed = distance/time
Calculation:
Let the speed of the second train is X kmph
Relative speed when train in opposite direction = 60 + X
Relative speed when train in opposite direction = (270+180)/10.8
60 + X = {(270+180)/10.8} × 18/5
60 + X = (450/10.8) × 18/5
60 + X = 150
X = 90 kmph