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In a consolidation test, when the load is changed from 50 kN/m2 to 100 kN/m2, then the void ratio changes from 0.80 to 0.60. The coefficient of compressibility will be:
1. 0.002 m2/kN
2. 0.003 m2/kN
3. 0.001 m2/kN
4. 0.004 m2/kN

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Correct Answer - Option 4 : 0.004 m2/kN

Concept:

The coefficient of compression index (Cc)

\({C_c} = \frac{{{e_1} - {e_2}}}{{{{\log }_{10}}\left( {\frac{{{{\bar \sigma }_1}}}{{{{\bar \sigma }_o}}}} \right)}}\)

The coefficient of compressibility (av)

\({a_v} = \left| {\frac{{\Delta e}}{{{{\bar \sigma }_o} - {{\bar \sigma }_1}}}} \right|\)

Calculation:

Given,

Δe = 0.2

\({{\bar \sigma }_o} = 50\) kN/m2

\({{\bar \sigma }_1} = 100\) kN/m2

Cc = 0.664 m2/kN

\({a_v} = \left| {\frac{{\Delta e}}{{{{\bar \sigma }_o} - {{\bar \sigma }_1}}}} \right| = \frac{{0.2}}{{50}} = 0.004\)

∴ av = 0.004 m2/kN

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