Correct Answer - Option 4 : 0.004 m
2/kN
Concept:
The coefficient of compression index (Cc)
\({C_c} = \frac{{{e_1} - {e_2}}}{{{{\log }_{10}}\left( {\frac{{{{\bar \sigma }_1}}}{{{{\bar \sigma }_o}}}} \right)}}\)
The coefficient of compressibility (av)
\({a_v} = \left| {\frac{{\Delta e}}{{{{\bar \sigma }_o} - {{\bar \sigma }_1}}}} \right|\)
Calculation:
Given,
Δe = 0.2
\({{\bar \sigma }_o} = 50\) kN/m2
\({{\bar \sigma }_1} = 100\) kN/m2
Cc = 0.664 m2/kN
\({a_v} = \left| {\frac{{\Delta e}}{{{{\bar \sigma }_o} - {{\bar \sigma }_1}}}} \right| = \frac{{0.2}}{{50}} = 0.004\)
∴ av = 0.004 m2/kN