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(a) An imaginary radioactive particle 23592X decays to form elements X1, X2, X3, X4, X5 and X6 by ejecting 2 beta particles, followed by an alpha particle and again 2 beta particles followed by an alpha particle. Represent the above in the form of nuclear equations. What is the mass number of X6

(b) List the isotopes and isobars formed in the above nuclear reactions.

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(a) 235 92X when α β particle is emitter mass number does not change but atomic number increases by 1 (isobar) 

∴ When 2 successive β particles decay mass number does not change (isobar) but atomic number increases by 2. 

Then α-particle decays, mass number decreases by 4 and atomic number decreases by 2. 

Ultimately when 2 β particles decays and la-particle decays

This means to change 235 92X to 235 92X1 here, atomic number remains same but mass number decreases by 4 

∴ In 6 steps [X → X1 → X2 → X3 →X4 →X5 →X5

Atomic number remains same but mass number decreases by 

6 x 4 = 24

(b) After every β decay isobar is formed and after α-decay isotope is formed 

∴ Total 12 isobars and 6 isotopes are formed.

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