Correct Answer - Option 1 : 506
Concept:
- 12 + 22 + 32 + ..... + n2 = \(\frac{n(n+1)(2n+1)}{6}\)
Calculation:
Here we have to find the sum of the series 1 + 4 + 9 +16 + 25 + 36 +......+ 121
The given series can be re-written as: 12 + 22 + 32 + ..... + 112
As we know that, 12 + 22 + 32 + ..... + n2 = \(\frac{n(n+1)(2n+1)}{6}\)
Here, n = 11
⇒ 12 + 22 + 32 + ..... + 112 = \(\frac{11 \times 12 \times 23}{6} = 506\)
Hence, option 1 is the correct answer.