Correct Answer - Option 1 : The distance from the point charge to A is half of the distance between charge and point B
The correct answer is option 1) i.e. The distance from the point charge to A is half of the distance between charge and point B
CONCEPT:
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Electric field strength is a measure of the electric field intensity at a point due to a charge. It is the amount of electric force produced per unit charge.
Electric field strength (E) at a point due to a point charge q is given by the formula:
\(E =\frac{q}{4\pi \epsilon_0 r^2}\)
q4πϵ0r2
Where r is the distance from the point charge to the point at which E is determined.
EXPLANATION:
If the charge remains constant,
\(E \propto \frac{1}{r^2}\)
So, if the electric field is four times greater at A,
\(E \propto4 \times \frac{1}{r^2} \Rightarrow E \propto \frac{1}{(r/2)^2}\)
- Therefore, the distance from the point charge to A is half the distance between the charge and point B.