Correct Answer - Option 4 :
\(5\frac{1}{3}\) hours
Given:
The first tap can fill it in 4 hours and the second tap can empty it in 16 hours
Concept:
If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank.
Calculation:
Part of the pot filled by both the taps in 1 hours = \(\frac{1}{4} - \frac{1}{{16}}\)
⇒ \(\frac{{4 - 1}}{{16}}{\rm{}} = {\rm{}}\frac{3}{{16}}\)
Time = (16/3) hours = \(5\frac{1}{3}\) hours
∴ The required time is \(5\frac{1}{3}\) hours.