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A pot has two taps. The first tap can fill it in 4 hours and the second tap can empty it in 16 hours. If both the taps are opened together, then what will be the time taken by pot to fill?
1. \(5\frac{1}{2}\) hours
2. 10 hours
3. 6 hours
4. \(5\frac{1}{3}\) hours

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Best answer
Correct Answer - Option 4 : \(5\frac{1}{3}\) hours

Given:

The first tap can fill it in 4 hours and the second tap can empty it in 16 hours

Concept:

If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank.

Calculation:

Part of the pot filled by both the taps in 1 hours = \(\frac{1}{4} - \frac{1}{{16}}\)

⇒ \(\frac{{4 - 1}}{{16}}{\rm{}} = {\rm{}}\frac{3}{{16}}\)

Time = (16/3) hours = \(5\frac{1}{3}\) hours

The required time is \(5\frac{1}{3}\) hours.

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