Correct Answer - Option 1 : 12 V
Concept:
In a uniformly loaded distributor fed at one end, the maximum total voltage drop = IR/2
In a uniformly loaded distributor fed at both ends, the maximum total voltage drop = IR/8
The maximum voltage drop in the case of uniformly loaded distributor fed at both ends is one-fourth of the maximum voltage drop in the case of uniformly loaded distributor fed at one end.
Calculation:
Length of distributor = 200 m = 0.2 km
Current supplied by distributor = 2 amperes/meter
Total current supplied by distributor (I) = 200 × 2 = 400 A
The resistance of single wire = 0.3 Ω/km
Total resistance = 0.3 × 0.2 = 0.06 Ω
Maximum voltage drop \( = \frac{{IR}}{2} = \frac{1}{2} \times 400 \times 0.06 = 12\;V\)