Correct Answer - Option 1 : 6
Case I : When 1 is at last pace..
There are two arrangements possible : 3 4 2 1, 2 4 3 1
Case II : When 2 is at last place.
There are three arrangements possible : 3 1 4 2, 3 4 1 2, 4 3 1 2
Case III : When 3 is at last place.
There is only one arrangement possible : 2 1 4 3
Therefore, total 6 different numbers are formed.
Hence, option 1 is the correct answer.