LIVE Course for free

Rated by 1 million+ students
Get app now
0 votes
25 views
in Mathematics by (117k points)
closed by
The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56 Find their present ages (in years).
1. 20, 35, 45
2. 16, 28, 36
3. 8, 20, 28
4. 8, 14, 18

1 Answer

0 votes
by (59.8k points)
selected by
 
Best answer
Correct Answer - Option 2 : 16, 28, 36

Given:

The ratio of present ages of three persons are in the ratio 4 : 7 : 9

8 years ago sum of their ages were = 56

Calculation:

Let us take the ratio of ages be 4x, 7x, 9x respectively

Ages of the person before 8 years = (4x - 8), (7x - 8), (9x - 8)

According to the question

⇒ (4x - 8) + (7x - 8) + (9x - 8) = 56 

⇒ 20x - 24 = 56

⇒ 20x = 80  

⇒ x = 4

Substituting the values in ratio

⇒ 4 × 4 : 7 × 4 : 9 × 4 = 16 : 28 : 36

∴ The present ages of 3 persons are 16, 28, 36 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...