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The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56 Find their present ages (in years).
1. 20, 35, 45
2. 16, 28, 36
3. 8, 20, 28
4. 8, 14, 18

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Correct Answer - Option 2 : 16, 28, 36

Given:

The ratio of present ages of three persons are in the ratio 4 : 7 : 9

8 years ago sum of their ages were = 56

Calculation:

Let us take the ratio of ages be 4x, 7x, 9x respectively

Ages of the person before 8 years = (4x - 8), (7x - 8), (9x - 8)

According to the question

⇒ (4x - 8) + (7x - 8) + (9x - 8) = 56 

⇒ 20x - 24 = 56

⇒ 20x = 80  

⇒ x = 4

Substituting the values in ratio

⇒ 4 × 4 : 7 × 4 : 9 × 4 = 16 : 28 : 36

∴ The present ages of 3 persons are 16, 28, 36 

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