Question

30 g of sugar was mixed in 180 ml water in a vessel A, 40 g of sugar was mixed in 280 ml of water in vessel B and 20 g of sugar was mixed in 100 ml of water in vessel C. The solution in vessel B is:
1. sweeter than that in C
2. Sweeter than that in A
3. as sweet as that in C
4. less sweet than that in C

Answer 1

Correct Answer - Option 4 : less sweet than that in C

Given 

Vessel A, sugar = 30 g, water = 180 ml

Vessel B, sugar = 40 g, Water = 280 ml 

Vessel C, Sugar = 20g , water = 100 ml 

Calculation 

⇒ Concentration of sugar in vessel A = 30/180 = 1/6 g/ml

⇒  Concentration of sugar in vessel B = 40/280 = 1/7 g/ml 

⇒  Concentration of sugar in vessel C = 20/100 = 1/5 g/ml

⇒ the more concentration of sugar means more sweetness of solution 

 ⇒ vessel C > vessel A > vessel B

∴ the solution of B is less sweet than solution C