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The mean of three numbers is 21. The range of this data set is 12 and difference between the two smallest numbers is 3. The greatest of three numbers is:
1. 27
2. 24
3. 25
4. 28

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Correct Answer - Option 4 : 28

Given:

The mean of three numbers  = 21.

Range = 12

Difference between the two smallest numbers = 3

Formula used:

Mean = (sum of observations)/(number of observations)

Range = (Highest observation) - (lowest observation)

Calculation:

Let the three numbers be x, y and z.

Where  x be the smallest number and z be the greatest number.

According to the question,

Mean = (sum of observations)/(number of observations)

⇒ 21 = (x + y + z)/3

⇒ x + y + z = 63     .....(1)

The range of this data set is 12,

Range = Highest observation - lowest observation

z – x = 12

⇒ z = 12 + x     .....(2)

Difference between the two smallest numbers = 3

y – x = 3

⇒ y = 3 + x    ....(3)

Using Equation(2) and (3) in (1) we get

x + (3 + x) + (12 + x) = 63

⇒ 3x + 15 = 63

⇒ 3x = 63 – 15

⇒ 3x = 48

⇒ x = 16

Putting the value of x in (3),

y = 3 + 16 = 19

Putting the value of x  in (2),

z = 12 + 16 = 28

∴The greatest of three numbers is 28.

 

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