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Find the smallest number which leaves the remainder 7 in each case when divided by 9, 11 ,18 ,17.
1. 3366
2. 3359
3. 3373
4. 3389

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Correct Answer - Option 3 : 3373

GIVEN:

Divisors = 9, 11, 18, 17

Remainder = 7

CONCEPT:

If we add the remainder with the L.C.M of the numbers, we will get the required number.

CALCULATION:

9 = 3 × 3 

11 = 11 × 1

18 = 2 × 3 × 3 

17 = 17 × 1

L.C.M of (9, 11, 18, 17) = 3 × 3 × 2 × 11 × 17 = 3366

⇒ Required number = 3366 + 7 = 3373

∴ The required smallest number is 3373.

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