Correct Answer  Option 1 : 20%
The correct answer is option 1) i.e. 20%
CONCEPT:

Kinetic energy is the energy possessed by a moving object. Kinetic energy (KE) is expressed as:
\(⇒ KE =\frac{1}{2} mv^2\)
Where m is the mass of the object and v is the velocity of the object.

Momentum: Momentum is the impact due to a moving object of mass m and velocity v.
 The momentum (p) of an object is expressed as:
⇒ p = mv
CALCULATION:
Let the initial and final kinetic energy of the particle be KE_{1} and KE_{2}. Similarly, the linear momentum will be p_{1} and p_{2}.
When the KE of the particle is increased by 44%, KE_{2} = 1.44KE_{1}
We know,
\(⇒ KE =\frac{1}{2} mv^2\)
Multiplying and dividing by m we get,
\(⇒ KE =\frac{1}{2} mv^2 \times \frac{m}{m} = \frac{p^2}{2m}\)
\(⇒ p =\sqrt{2mKE}\)
⇒ p ∝ √KE
 The percentage increase in linear momentum
\(\Rightarrow\Delta p\%=\frac{p_2  p_1}{p_1} \times 100 = \frac{\sqrt{KE_2}  \sqrt{KE_1}}{\sqrt{KE_1}} \times 100 \)
\(\Rightarrow \Delta p\%=\frac{\sqrt{1.44KE_1}  \sqrt{KE_1}}{\sqrt{KE_1}} \times 100 =\frac{\sqrt{1.44}  \sqrt{1}}{\sqrt{1}} \times 100 = \frac{1.2 1}{1} \times 100 = 20\%\)