Correct Answer - Option 4 : 4096
Concept:
Let A and B are two sets, having a number of elements n(A) and n(B) respectively.
Then, the number of distinct relation = \(\rm 2^{n(A)\times n(B)}\)
Calculation:
Here, P = {1, 2, 3} and Q = {4, 5, 6, 7}
n(P) = 3
n(Q) = 4
∴ Number of distinct relation = \(\rm 2^{n(A)\times n(B)}\)
\(\rm 2^{n(P)\times n(Q)} \\=2^{3\times 4}\)
= 212
= 4096
Hence, option (4) is correct.