Correct Answer - Option 4 : H
1.5
Concept:
Discharge over an Ogee spillway is given by:
\(Q = \;\frac{2}{3}{C_d}\sqrt {2g} LH_e^{\frac{3}{2}}\)
He = Total head upstream of the crest.
L = crest width
Cd = coefficient of discharge
C = constant, which is equal to \(\frac{2}{3}{C_d}\sqrt {2g}\)<!--[if gte msEquation 12]> H32<![endif]--><!--[if !msEquation]-->
∴ Discharge Q is proportional to H1.5<!--[endif]-->